If I can remember correctly from a decade ago, there is a formula as relayed to me by someone that goes like this: Spine of a wooden arrow is measured across a 26" span to equate spine to bow weight. So if one's draw is 26" and the bow weight is 49lbs, a 49 lb spined arrow is required. For each inch variance from a 26" draw, the arrow spine increases or decreases by about 3 to 4 lbs. Therefore, for a 26.5" draw you would need about 1.5 to 2 lbs more arrow spine than your 49lb bow. This of course will vary some depending on how center cut your bow is and maybe some other factors. But it looks like 50-55 lb spine is what you need. Disclaimer: I'm old!