OK, I got two ways, the same thing but different:
A) Distance knock throat to balance point divided by shaft length ( arrow only ) minus .5 X 100 = % FOC {taken from an older Ashby document}
B) Find balance point from knock throat to point of balance. Find shaft total length. Divide shaft length by 2 and subtract from balance point. That is your FOC length. Divide FOC length by shaft length and multipy by 100, that is % FOC.
Anyway, it is simple to calculate and makes me feel prety good about my set up, about 480 grain arrow, from about 48 pound bow with 20 % FOC and single bevel broad heads. If I can hit what I aim at, I will be ready Wisconsin's white-tails.
Bob.