Originally posted by reddogge:
I'd like to do a shooting experiment like swampthing did but I don't have a bale big enough to do it. I'd like the distances calculated every 5 yards from his or anyone's point on distance. I believe the highest point of the arc is not the mid range but more towards the target due to increased acceleration in the beginning and less acceleration and more drag at the end.
In other words the inches over the target will be less from 5-10 yards from the bow than 20-25 yards from the bow so the arc is not a perfect parabola peaking at exactly midpoint of your point on.
Does this make sense?
Looking at a low coefficient bullet at 500 fps (the lowest I can compute)and a 50 yard zero (again the shortest distance I can compute), mid-range trajectory is highest at 30 and 35 yards. I used a 6" scope height to illustrate this for myself and it points out that bullet or bow, if you sling something at a target, it will necessarily have a curved arc to the target.
You are, in my opinion, correct in your assumptions that the midrange is going to be beyond the halfway point, but as the old (before ballistic calculators) systems implied, mid-range is just that, mid-range, not specifically half way but close enough for government work without the budget.
While I was playing games with myself in the neibhors guava patch years ago with wood arrows, I come to conclusion that it didn't matter that midrange was 4 yards beyond halfway or 6 yards beyond halfway, they still got tangled up with lower hanging branches... The only way to have solved that pesky parabola, was to increase the speed of the slingee... and alas... the desired limitations of the longbow prevail and I moved on to clearer pathways.
Not to be disagreeable, but you are correct in the reduced acceleration towards the target, but that isn't a result of increased drag. Drag is a function of speed in air and as the arrow slows down, so too does the drag effect or coefficient might be proper... the increased drag at the launch being greatly of influence of the decelerated values later on...
As for arrow acceleration, I'm not certain, but I think that once the arrow leaves the string, acceleration is fini... and thus it's all deceleration from there I think.
Aloha... :cool: