In my photo there is a James Parker Bamboo Back/Bamboo Belly bow (the bow on the bottom) I got as a blank and finished myself. It came out 48# @ 25". I took measurments of all of his lams with a dial caliber and attempted to come up with my own bow hoping to come out with about the same poundage (bow on top in photo). The boo is flattened from 1/8" to about 1/16. I have osage lams directly below the boo on the back & directly above the boo on the belly .095 tapered .002 per inch purchased from Kenny M. In the middle of these I have a piece of IPE .156 center of risor, midlimb .095, and about .045 at tips. This piece of IPE I tapered myself the best I could by hand without any tapering machine. I know that leaves a lot of room for error, but I did do another bow the same way and it came out great. I did add a tapered tip wedge 12" long starting at .070 (no wedges on Parker bow). I took thickness measurements of both bows at the fade outs, midlimb, & the tips. Except for the tips, they are about the same ( my tips are a little wider because of the wedges). I should mention also that the Parker bow has the same wood combinations as mine. Having said all this, I am at a loss of why my bow shows about 55-59 lbs at only 3 inches or so of brace height which would make it over 100 lbs @ 25". Does the fact that my bow has a lot more reflex have anything to do with this? The added tip wedges? Any help would be appreciated.