Regarding how many staves you can get, a 10" diameter tree has a circumference of ~30".
If you split it into quarters each blank would have an arc length of 7.85" and a chord length of ~7".
If you split it into 8 sections each blank would have an arc length of 3.9" and a chord length of 3.8"
Refer to this article to see what I mean by arc length (s) and chord length (c)
http://en.wikipedia.org/wiki/Circular_segment Chord length is related to the maximum width of the bow you can make, so lets say to be safe, you want to know the max limb width for a 1" thick limb (obviously you wont need 1" thick, but this is to make the calculation conservative).
For maximum Limb width (LWm), Take chord length (c), divide by diameter of the log(D), then multiply by (diameter of the log (D) - thickness of the limb (Tl) or:
LWm = c ((D - Tl)/D)
for a 10" diameter log, split into 8 pieces as described, and figuring a 1" thick limb (to be safe)
LWm = 3.8" ((10-1)/10)
LWm = 3.8" (9/10)
LWM = 3.42" .... so once you square off the stave you'd have a maximum of 3.42" width.
For a 6" diameter log, split into 8 pieces as described below, and figuring 1" thick limbs (to be safe)
LWm = 2.29" ((6-1)/6)
LWm = 2.29" (5/6)
LWM = 1.9" .... so once you square off the stave you'd have a maximum of 1.9" width.
Based on these calculations, a 10" tree should yield 8 very ample staves. That will leave you alot of room to remove wood from the sides of the stave.
I would probably split the stave into quarters, saw off a belly split from each quarter, then split the outer portion of each quarter into 2 staves. Like this:
http://img.photobucket.com/albums/v86/Timotoad/osage%2009/osage014.jpg That would be enough for 8 selfbows and 4 backed bows. You could probably go even crazier but I wouldn't risk it. Thats alot of bows. and with stave prices for good yew, thats big money.
For a 6" log the circumference is ~19"
If you split it into quarters each blank would have an arc length of ~4.75" and a chord length of ~4.24".
If you split into 6, each blank would have an arc length of ~ 3.16" and a chord length of ~3"
If you split it into 8 sections each blank would have an arc length of ~2.375" and a chord length of 2.29"
For a 6" diameter tree I'd probably split it into thirds, saw off one belly split each, then split the outer staves into 2 each, yielding 6 outer staves and 3 belly splits. Again, you could probabyl go crazier and split it into 8 staves and 4 belly splits, but I wouldn't risk it personally.
I know that was long but hope that helps with deciding the age old question of "how many staves are in this log"