Someone please explain ...
I can't tell how many times I've heard that bows , typically over 65 lbs, become less efficient than lighter bows .
It could be because heavier bows tend to have heavier limbs, which per se sucks up some of the speed/energy
Nor am I understanding , apparently , what " efficiency " means in this context .
Thoughts ?
You are right, we should first define what we mean by efficiency.
The way I intended it, efficiency is the proportion of stored energy that the bow manages to give back to the arrow. Let me explain:
You pull the string, and you get at full draw; right now the bow has potential energy, which is waiting to be released; the moment you loose the string, the fibers of the limbs go back to where they were; that potential energy, stored by the deformed limbs (deformed as you are at full drawn) will be transmitted to the arrow. Not all of it will end up in the arrow though; there will always be losses (e.g. the attrition with the air). If the arrow is really light, it will leave the bow before all its fibers have released their energy, therefore the "surplus" will end up on the bow itself (and that's why if the arrow is too light you can damage the bow, similarly to a dry fire).
So, the efficiency of a bow is determined by the proportion of potential energy that is actually transmitted to the arrow. I completely agree with Pavan, one of the variables determining the efficiency is the design of the bow.
Hope this makes sense. Are there any physicists among us, by any chance?
That would help