This may be an odd question, but what do you guys think about attempting to take a significant amount of weight off a commercially produced bow?
There is a takedown recurve in the local classifieds that is 65# @28". It is a nice looking bow in excellent condition and the price has gotten very reasonable (probably because it is just too heavy for the vast majority of archers). If I could get that down to the low 50# range it would be a great buy for me. But that supposes I can drop 12-15# off without screwing it up.
All thoughts/experiences/ideas welcome.
Thanks,
Mark
I've never taken more than a few pounds off of any bow and that usually just in the tillering and finishing process. But that doesn't mean I don't have opinions.
Being a TD, I suppose you will need to reduce width the full length of the limbs including the wedges? That would then might call for some mods to the riser to match the limb widths?
It should be easy to calculate given that draw weight is linear to limb width.
It seems that once you calculate the amount of reduction you would need to apply it as a percentage of existing limb width the for the full length of the limb? If that's the case, it might be a concern with the existing width of the tips? IOW, is there enough meat there to reduce the desired percentage?
You could reduce further by trapping the limbs? In trapping you might want to apply the same percentage concept?
This percentage idea is meant to preserve the existing dynamics of the limbs?
Note the plethora of question marks above. This post is just me letting my brain wander through a process. Watch for enlightening critique of my thoughts!